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197-RisingTemperature.sql
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62 lines (59 loc) · 1.98 KB
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-- 197. Rising Temperature
-- Table: Weather
-- +---------------+---------+
-- | Column Name | Type |
-- +---------------+---------+
-- | id | int |
-- | recordDate | date |
-- | temperature | int |
-- +---------------+---------+
-- id is the primary key for this table.
-- This table contains information about the temperature on a certain day.
-- Write an SQL query to find all dates' Id with higher temperatures compared to its previous dates (yesterday).
-- Return the result table in any order.
-- The query result format is in the following example.
--
-- Example 1:
-- Input:
-- Weather table:
-- +----+------------+-------------+
-- | id | recordDate | temperature |
-- +----+------------+-------------+
-- | 1 | 2015-01-01 | 10 |
-- | 2 | 2015-01-02 | 25 |
-- | 3 | 2015-01-03 | 20 |
-- | 4 | 2015-01-04 | 30 |
-- +----+------------+-------------+
-- Output:
-- +----+
-- | id |
-- +----+
-- | 2 |
-- | 4 |
-- +----+
-- Explanation:
-- In 2015-01-02, the temperature was higher than the previous day (10 -> 25).
-- In 2015-01-04, the temperature was higher than the previous day (20 -> 30).
-- Create table If Not Exists Weather (id int, recordDate date, temperature int)
-- Truncate table Weather
-- insert into Weather (id, recordDate, temperature) values ('1', '2015-01-01', '10')
-- insert into Weather (id, recordDate, temperature) values ('2', '2015-01-02', '25')
-- insert into Weather (id, recordDate, temperature) values ('3', '2015-01-03', '20')
-- insert into Weather (id, recordDate, temperature) values ('4', '2015-01-04', '30')
-- Write your MySQL query statement below
SELECT
w2.id
FROM
Weather AS w1,
Weather AS w2
WHERE
w2.temperature > w1.temperature AND
DATEDIFF(w2.recordDate,w1.recordDate) = 1
SELECT
today.id AS Id
FROM
Weather yesterday,
Weather today
WHERE
yesterday.recordDate = DATE_SUB(today.recordDate,INTERVAL 1 DAY) AND
today.Temperature > yesterday.Temperature